\(\int (c+d x)^m \cosh (a+b x) \, dx\) [78]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [F]
   Fricas [A] (verification not implemented)
   Sympy [F(-2)]
   Maxima [A] (verification not implemented)
   Giac [F]
   Mupad [F(-1)]

Optimal result

Integrand size = 14, antiderivative size = 110 \[ \int (c+d x)^m \cosh (a+b x) \, dx=\frac {e^{a-\frac {b c}{d}} (c+d x)^m \left (-\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {b (c+d x)}{d}\right )}{2 b}-\frac {e^{-a+\frac {b c}{d}} (c+d x)^m \left (\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {b (c+d x)}{d}\right )}{2 b} \]

[Out]

1/2*exp(a-b*c/d)*(d*x+c)^m*GAMMA(1+m,-b*(d*x+c)/d)/b/((-b*(d*x+c)/d)^m)-1/2*exp(-a+b*c/d)*(d*x+c)^m*GAMMA(1+m,
b*(d*x+c)/d)/b/((b*(d*x+c)/d)^m)

Rubi [A] (verified)

Time = 0.07 (sec) , antiderivative size = 110, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {3388, 2212} \[ \int (c+d x)^m \cosh (a+b x) \, dx=\frac {e^{a-\frac {b c}{d}} (c+d x)^m \left (-\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (m+1,-\frac {b (c+d x)}{d}\right )}{2 b}-\frac {e^{\frac {b c}{d}-a} (c+d x)^m \left (\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (m+1,\frac {b (c+d x)}{d}\right )}{2 b} \]

[In]

Int[(c + d*x)^m*Cosh[a + b*x],x]

[Out]

(E^(a - (b*c)/d)*(c + d*x)^m*Gamma[1 + m, -((b*(c + d*x))/d)])/(2*b*(-((b*(c + d*x))/d))^m) - (E^(-a + (b*c)/d
)*(c + d*x)^m*Gamma[1 + m, (b*(c + d*x))/d])/(2*b*((b*(c + d*x))/d)^m)

Rule 2212

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> Simp[(-F^(g*(e - c*(f/d))))*((c
+ d*x)^FracPart[m]/(d*((-f)*g*(Log[F]/d))^(IntPart[m] + 1)*((-f)*g*Log[F]*((c + d*x)/d))^FracPart[m]))*Gamma[m
 + 1, ((-f)*g*(Log[F]/d))*(c + d*x)], x] /; FreeQ[{F, c, d, e, f, g, m}, x] &&  !IntegerQ[m]

Rule 3388

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + Pi*(k_.) + (f_.)*(x_)], x_Symbol] :> Dist[I/2, Int[(c + d*x)^m/(E^(
I*k*Pi)*E^(I*(e + f*x))), x], x] - Dist[I/2, Int[(c + d*x)^m*E^(I*k*Pi)*E^(I*(e + f*x)), x], x] /; FreeQ[{c, d
, e, f, m}, x] && IntegerQ[2*k]

Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \int e^{-i (i a+i b x)} (c+d x)^m \, dx+\frac {1}{2} \int e^{i (i a+i b x)} (c+d x)^m \, dx \\ & = \frac {e^{a-\frac {b c}{d}} (c+d x)^m \left (-\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {b (c+d x)}{d}\right )}{2 b}-\frac {e^{-a+\frac {b c}{d}} (c+d x)^m \left (\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {b (c+d x)}{d}\right )}{2 b} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.05 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.93 \[ \int (c+d x)^m \cosh (a+b x) \, dx=\frac {e^{-a-\frac {b c}{d}} (c+d x)^m \left (e^{2 a} \left (-\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {b (c+d x)}{d}\right )-e^{\frac {2 b c}{d}} \left (b \left (\frac {c}{d}+x\right )\right )^{-m} \Gamma \left (1+m,\frac {b (c+d x)}{d}\right )\right )}{2 b} \]

[In]

Integrate[(c + d*x)^m*Cosh[a + b*x],x]

[Out]

(E^(-a - (b*c)/d)*(c + d*x)^m*((E^(2*a)*Gamma[1 + m, -((b*(c + d*x))/d)])/(-((b*(c + d*x))/d))^m - (E^((2*b*c)
/d)*Gamma[1 + m, (b*(c + d*x))/d])/(b*(c/d + x))^m))/(2*b)

Maple [F]

\[\int \left (d x +c \right )^{m} \cosh \left (b x +a \right )d x\]

[In]

int((d*x+c)^m*cosh(b*x+a),x)

[Out]

int((d*x+c)^m*cosh(b*x+a),x)

Fricas [A] (verification not implemented)

none

Time = 0.09 (sec) , antiderivative size = 168, normalized size of antiderivative = 1.53 \[ \int (c+d x)^m \cosh (a+b x) \, dx=-\frac {\cosh \left (\frac {d m \log \left (\frac {b}{d}\right ) - b c + a d}{d}\right ) \Gamma \left (m + 1, \frac {b d x + b c}{d}\right ) - \cosh \left (\frac {d m \log \left (-\frac {b}{d}\right ) + b c - a d}{d}\right ) \Gamma \left (m + 1, -\frac {b d x + b c}{d}\right ) - \Gamma \left (m + 1, \frac {b d x + b c}{d}\right ) \sinh \left (\frac {d m \log \left (\frac {b}{d}\right ) - b c + a d}{d}\right ) + \Gamma \left (m + 1, -\frac {b d x + b c}{d}\right ) \sinh \left (\frac {d m \log \left (-\frac {b}{d}\right ) + b c - a d}{d}\right )}{2 \, b} \]

[In]

integrate((d*x+c)^m*cosh(b*x+a),x, algorithm="fricas")

[Out]

-1/2*(cosh((d*m*log(b/d) - b*c + a*d)/d)*gamma(m + 1, (b*d*x + b*c)/d) - cosh((d*m*log(-b/d) + b*c - a*d)/d)*g
amma(m + 1, -(b*d*x + b*c)/d) - gamma(m + 1, (b*d*x + b*c)/d)*sinh((d*m*log(b/d) - b*c + a*d)/d) + gamma(m + 1
, -(b*d*x + b*c)/d)*sinh((d*m*log(-b/d) + b*c - a*d)/d))/b

Sympy [F(-2)]

Exception generated. \[ \int (c+d x)^m \cosh (a+b x) \, dx=\text {Exception raised: TypeError} \]

[In]

integrate((d*x+c)**m*cosh(b*x+a),x)

[Out]

Exception raised: TypeError >> cannot determine truth value of Relational

Maxima [A] (verification not implemented)

none

Time = 0.07 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.72 \[ \int (c+d x)^m \cosh (a+b x) \, dx=-\frac {{\left (d x + c\right )}^{m + 1} e^{\left (-a + \frac {b c}{d}\right )} E_{-m}\left (\frac {{\left (d x + c\right )} b}{d}\right )}{2 \, d} - \frac {{\left (d x + c\right )}^{m + 1} e^{\left (a - \frac {b c}{d}\right )} E_{-m}\left (-\frac {{\left (d x + c\right )} b}{d}\right )}{2 \, d} \]

[In]

integrate((d*x+c)^m*cosh(b*x+a),x, algorithm="maxima")

[Out]

-1/2*(d*x + c)^(m + 1)*e^(-a + b*c/d)*exp_integral_e(-m, (d*x + c)*b/d)/d - 1/2*(d*x + c)^(m + 1)*e^(a - b*c/d
)*exp_integral_e(-m, -(d*x + c)*b/d)/d

Giac [F]

\[ \int (c+d x)^m \cosh (a+b x) \, dx=\int { {\left (d x + c\right )}^{m} \cosh \left (b x + a\right ) \,d x } \]

[In]

integrate((d*x+c)^m*cosh(b*x+a),x, algorithm="giac")

[Out]

integrate((d*x + c)^m*cosh(b*x + a), x)

Mupad [F(-1)]

Timed out. \[ \int (c+d x)^m \cosh (a+b x) \, dx=\int \mathrm {cosh}\left (a+b\,x\right )\,{\left (c+d\,x\right )}^m \,d x \]

[In]

int(cosh(a + b*x)*(c + d*x)^m,x)

[Out]

int(cosh(a + b*x)*(c + d*x)^m, x)